Two molecules of acetone in the presence of dilute $NaOH$ give the product:

  • A
    $4-$Methyl$-2-$pentanone
  • B
    $4-$Hydroxy$-2-$pentanone
  • C
    $3-$Hydroxy isopropyl propanone
  • D
    $4-$Hydroxy$-4-$methyl$-2-$pentanone

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The reaction of acetaldehyde with conc. $KMnO_4$ gives

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